… in a thin-walled circular cross-section

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… in a thin-walled circular cross-section#

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Fig. 47 Figure 6.8 Hartsuijker and Welleman (2007)#

The shear stress due to torsion in a circular cross section:

\[\tau(r) = \frac{M_tr}{2 \pi R^2 t} = \frac{M_tr}{I_p}\]

This is treated in chapter 6.2.1 of the book Engineering Mechanics Volume 2 (Hartsuijker and Welleman, 2007).

Exercises#

Exercises 6.5 - 6.8 and 6.15 of the book Engineering Mechanics Volume 2 (Hartsuijker and Welleman, 2007). Answers are available on this website.